we are currently implementing a non-supersymmetric model including, in addition to the Standard Model, a couple of scalars and new fermions. One important feature of this model is that neutrino masses are generated radiatively at the one-loop level. In a simple case, it turns out that only two neutrinos will have masses, while the first one remains massless (roughly, this is due to the number of degrees of freedom available to generate the masses).
We have implemented the model in SARAH and generated a SPHENO version from it. While testing, we had a look into certain couplings on the Mathematica level, after running the model in SARAH. In particular, we looked at the couplings which allow to generate the neutrino masses, which are the couplings between Standard Model fermions (leptons, neutrinos), a new fermion, and a new scalar.
While the coupling structure looks allright, we are confused about the following point. We first ask to display the coupling in the form:
In this example, "Fe" is a Standard Model lepton, "FXc" a new charged fermion, and "P0" a neutral scalar. "cg1", "cg2" are coupling parameters, while "Ue", "Ve", "ZSc" are mixing matrices associated to the leptons and new scalars.In[4]:= Vertex[{Fe, bar[FXc], P0}]
Out[4]= {{Fe[{gt1}], bar[FXc], P0[{gt3}]}, {I conj[ZSc[gt3, 1]] sum[j1, 1, 3, cg1[j1] conj[Ve[gt1, j1]]], PL}, {-((I conj[ZSc[gt3, 2]] sum[j1, 1, 3, conj[cg3[j1]] Ue[gt1, j1]])/Sqrt[2]), PR}}
We then ask to display the conjugated coupling, which gives:
It all looks normal concerning complex conjugation, except the fact that the scalar mixing matrix "ZSc" is not conjugated w.r.t. to the first expression. However, we would expect this matrix also to be conjugated.In[6]:= Vertex[{bar[Fe], FXc, P0}]
Out[6]= {{bar[Fe[{gt1}]], FXc,
P0[{gt3}]}, {-((
I conj[ZSc[gt3, 2]] sum[j1, 1, 3, cg3[j1] conj[Ue[gt1, j1]]])/Sqrt[
2]), PL}, {I conj[ZSc[gt3, 1]] sum[j1, 1, 3,
conj[cg1[j1]] Ve[gt1, j1]], PR}}
Is there something wrong with our model, or are we missing something?
If needed, we can provide more information, of course.
Best regards,
Björn